$\int\frac{\left(6x^2+50\right)}{\left(x+3\right)\left(x^2+4\right)}dx$
$\int \frac { x ^ { 2 } + 3 } { x + 1 } d x$
$\left(\frac{1}{8}y^9+3y^{20}\right)^2$
$\left(\frac{3}{5}x^2-\frac{1}{2}\right)\left(\frac{3}{5}x^2+\frac{1}{2}\right)$
$0.08\cdot0.08$
$2x+20=-30$
$5-3+7-1+9-11-34$
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