$x^4-x^3+4x+2$
$8x+2\le4x+10$
$-75+3$
$04\sen^{2}\theta+1=4\sen\theta$
$\frac{x^3-x\:+1}{x^2+1}$
$\int\left(x-2\right)senx\:dx$
$16x\:+\:11=18x-9$
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