$\frac{y+2}{y-3}+\frac{y-2}{3-y}$
$-20^2$
$\frac{-12a^4b^2}{-3a^2b}$
$9y^2-10y+16$
$\int\left(1-4x^2\right).e^{-x}dx$
$+0-\left(-1155\right)$
$\frac{1}{\sec\left(b\right)-\tan\left(b\right)}=\frac{1+\sin\left(b\right)}{\cos\left(b\right)}$
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