$\int\frac{8x}{\left(2x-3\right)^2}dx$
$\left(-17\right)+8+\left(-12\right)-\left|\left(-16\right)-\left(-4\right)\right|$
$\left(2u^3\right)^3\cdot u^2$
$64v^2-25$
$\frac{50x}{x}$
$5x-1\ge-2$
$\left(9x-4\right)\left(9x+11\right)$
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