$x\frac{4}{3}x-3$
$\lim_{g\to0}\left(\frac{\left|3+g\right|-\left|3\right|}{g}\right)$
$2+0-7+8-10-15+14-20+15$
$\frac{\tan b}{1+\sec b}-\frac{\tan b}{1-\sec b}=\frac{2}{\sin b}$
$\lim_{x\to0}\left(\frac{3-x}{x^2}\right)$
$5cosxtanx-7tanx=0\:$
$2^2.3^4$
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