$\left(3x-35\right)^2$

$\left(9m-6n+7p\right)^2$

$3\frac{dy}{dx}+2xy=x\left(y\right)^{-2}$

$2x^2-72x^2$

$\left(\frac{x^2-25}{x^2-25}\right)\left(\frac{2x+4}{2x-10}\right)$

$-3\left\{-2+6\left[-3+2-\left(-3+0\right)+1\right]+4\right\}+0$

$\frac{16}{-2}\cdot\frac{-9}{-3}$