$\lim_{x\to0}\left(\frac{4x}{3-4e^x}\right)$
$9x\left(xy\right)^2-z^2$
$\frac{dy}{dx}=\frac{2x}{y}+\frac{2y}{x}$
$\lim_{x\to infinity}\left(\sqrt{9x^2+2x}-3x\right)$
$\frac{2x^2-7x-15}{x-5}$
$90x-1=179$
$-51-\left(-61\right)$
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