$\frac{x^2}{4}-xy+y^2$
$\frac{1-16z^2}{1+4z}$
$1+\cos\left(x\right)-\sin^2\left(x\right)$
$2x^2-10x+12$
$\left(64\cdot x^2\right)-\left(25\cdot y^2\right)$
$-8\left(7-15\right)$
$a-bcosx=y$
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