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We could not solve this problem by using the method: Integrals by Partial Fraction Expansion
Since the upper limit of the integral is less than the lower one, we can rewrite the limits by applying the inverse property of integration limits: If we invert the limits of an integral, it changes sign: $\int_a^bf(x)dx=-\int_b^af(x)dx$
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$-\int_{2}^{3}\frac{x^2-1}{x-1}dx$
Learn how to solve definite integrals problems step by step online. Integrate the function (x^2-1)/(x-1) from 3 to 2. Since the upper limit of the integral is less than the lower one, we can rewrite the limits by applying the inverse property of integration limits: If we invert the limits of an integral, it changes sign: \int_a^bf(x)dx=-\int_b^af(x)dx. Rewrite the expression \frac{x^2-1}{x-1} inside the integral in factored form. Expand the integral \int\left(x+1\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral of a constant is equal to the constant times the integral's variable.