$6\:+\:-8\:+\:-9\:+\:4\:+\:-5$

$\int\left(\frac{sec^2x+\sec\left(x\right)\tan\left(x\right)}{\sec\left(x\right)+\tan\left(x\right)}\right)dx$

$6^2+18x^3$

$\ln\left(x+2\right)+\ln\left(3x-12\right)=\ln\left(2x-2\right)+\ln x$

$\int\left(2-t^2\right)e^{\left(6t-t^3\:\right)}\:dt$

$n2+3n+2n$

$\left(-88\right)\::\:\left(-2\right)$