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Integrate the function $\frac{\pi }{982^{\frac{3}{2}}}-\frac{\pi}{9}$ from 0 to $3$

Step-by-step Solution

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asinh
acosh
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Final Answer

$-1.046891$
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Step-by-step Solution

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We could not solve this problem by using the method: Integration by Substitution

1

Simplifying

$\int_{0}^{3}\left(\frac{\pi }{\sqrt{\left(982\right)^{3}}}-\frac{\pi}{9}\right)dx$

Learn how to solve definite integrals problems step by step online.

$\int_{0}^{3}\left(\frac{\pi }{\sqrt{\left(982\right)^{3}}}-\frac{\pi}{9}\right)dx$

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Learn how to solve definite integrals problems step by step online. Integrate the function pi/(982^(3/2))-pi/9 from 0 to 3. Simplifying. Simplify the expression inside the integral. The integral \int_{0}^{3}\frac{1}{9795}dx results in: 0.000306. The integral \int_{0}^{3}-\frac{\pi}{9}dx results in: -\frac{\pi}{3}.

Final Answer

$-1.046891$

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Function Plot

Plotting: $\frac{\pi }{982^{\frac{3}{2}}}-\frac{\pi}{9}$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

2. See formulas

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