$\left(4x^{-4}y^8\right)^{-2}$
$-65+32-7-19+39+6+20$
$\frac{4x-2}{2x+1}$
$\left(3x+1\right)\cdot\left(3x+1\right)$
$\frac{x^2}{x-3}-\frac{5x-6}{x-3}$
$tan^2xcotx=tanx$
$4x^2-16x-36$
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