$\sqrt{25x}^4y^5$
$fac\left(x^5+2x^4-27x^3+41x^2-14x-3\right)$
$\left(3.6\right)\left(3.6\right)$
$x^2=x^2\left(2\right)+625$
$0.3223341283353674+0.50572$
$x^{-2}\left(\frac{dy}{dx}\right)+3y=6$
$6.8x\:-\:4\:+\:3x\:-\:1.2$
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