$\left(3x^3+6\right)^2$
$\left(\frac{c^3}{c^5}\right)^3$
$-13+\frac{-5-7-9}{-7}+\frac{-12}{4}$
$\frac{dy}{dx}=\frac{1+y^2}{\left(1-y\right)x}$
$12ab\:-\:9ac\:$
$\sin x=\frac{5}{7}$
$log\left(tan^2x\right)+2=0$
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