$\sqrt[3]{\frac{x}{x}}$
$7x+4\:>\:9x\:+16$
$t_{subir}=v_{ov}$
$\int\left[2x+5\right]\left[7x-3\right]dx$
$\int\left(4x^3\left(x^4-3\right)\right)dx$
$6^{-x}=36^{x+6}$
$\lim_{x\to0}\left(\frac{sinx}{38.4x}\right)^{\frac{1}{x}}$
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