$\frac{1}{2\sin10}-2\sin\left(70\right)$

$\frac{6}{x^2-4x+3}$

$\frac{dy}{dx}=x+4y+2$

$\frac{1}{sin\left(x\right)}-\frac{cos\left(x\right)}{sin\left(x\right)}=\frac{sin\left(x\right)}{1+cos\left(x\right)}$

$\lim_{x\to\infty}\left(\left(-\pi\right)^x\right)$

$\left(2y^2x-3\right)dx+\left(2yx^2+4\right)dy=0;\:y\left(1\right)=-2$

$-4x^2+5x-6$