$u+3=\frac{u^2+3u-4}{u-2}+\frac{3}{u+2}$
$-19-10+8+12-15-20$
$\left(+9\right)-\left(-11\right)$
$\left(2a^2+5b\right)^5$
$\frac{3m^{-3}n^2}{2m^{-4}n^2}$
$\cos\left(x+20\right)=0.33$
$4x^5+3x^4-32x^3-24x^2$
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