$y'+9tan\left(9x\right)y=-7cos\left(9x\right)$

$x^2+8x=c$

$\int\left(3x^2\cdot\cos\left(4x^3+9\right)\right)dx$

$\int x^3\left(x^2+36\right)dx$

$\left(6x^2+xy+2y^2\right)\left(y+2x\right)$

$\:9\:-3\:-\:8\:\left[4\:-\:3\:+\:\left(5\:+\:2\:-\:10\right)\:-\:2\:\left(4\:-\:5\right)\:-\:3\right]\:+\:4\:-\:8\:+\:2$

$3-1\cdot1-1\cdot1^{2}$