$\left(4b+10\right)\left(4b-5\right)$
$\frac{\left(-1\right)^4\left(x^4\right)\left(3x^{-2}\right)\left(-1\right)^7}{1}$
$( 8 - 10 ) - ( 4 + 8 ) - ( 5 - 7 )$
$y^2-7y+7y-49$
$8b^3+5a^2+-7a^2+-3b^3+3c-b^2$
$\int8x\left(2x^2-2\right)^5dx$
$sec\left(\arctan\left(4x\right)\right)$
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