$\left(4\right)\left(2\right)\left(3\right)^2$
$7\left(x+8\right)=-7$
$\int\:\frac{2x}{\left(3+x^2\right)^2}dx$
$y=x^5+2x^{-3}\:$
$2x^3+4x^2-8x-6$
$-5+-5+2+7+-35+65+-54$
$9a^2-1$
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