$\left(3u^{-1}v^3\right)^4$
$\frac{\left(-x^2+x+1\right)}{\left(x+3\right)}$
$14-12+14+1-9-1$
$x2-6x\ge-5\:$
$\sqrt[4]{36m^8}n^4$
$3\tan^2\left(x\right)-2\tan\left(x\right)=2$
$\lim_{x\to0}\left(\frac{4xcos2x-sen2x}{4x^3}\right)$
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