$\frac{9a^2-6}{3a}$

$\frac{300}{\left(3x+25\right)^2}$

$\left(x^2-4x+3\right)\left(x-1\right)\left(2-x\right)\left(x^2+4\right)$

$7x-2\left(1-3x\right)\le2x+3$

$\frac{d^3}{dx^3}\left(-\frac{1}{20}x^6-\frac{1}{6}x^2+\frac{3}{16}x-x^3\right)$

$-6-3-9-4-\left(-8\right)$

$\int\left(\frac{\sqrt{x}}{x-4}\right)dx$