$x^3-19x-30$
$8 x ^ { 3 } + 6 x$
$\frac{\cos\left(x\right)+\sin\left(x\right)^3-\sin\left(x\right)}{\sin\left(x\right)}=\cot\left(x\right)-\cos\left(x\right)^2$
$\lim_{x\to5}\left(\frac{x^2+10x+25}{x^2-10x+25}\right)$
$\left[5-7.\left(-3\right)-\left(5-3\right)\right]$
$\left(\frac{1}{2}x+3\right)\left(\frac{1}{2}x-6\right)$
$9a+3b-3c$
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