$-5+\left(-2\right)-\left(+12\right)-\left(-10\right)+8$
$-25\cdot7$
$17-\left(-4-6+3\right)+\left(-8+1\right)$
$19ab+22ab-12ab+3ab$
$x^1^0\:+\:8\:x^6\:+\:16\:x^2$
$\lim_{x\to\infty}\left(1+\frac{4}{x}\right)^{\frac{x}{8}}$
$3x\:-2\left(x\:-\:2\right)\:\ge\:2x$
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