$\sqrt{2}\cos\left(x-\frac{\pi}{4}\right)=\sin\left(x\right)+\cos\left(x\right)$
$\frac{152}{255}^3+1.78823529412+8$
$\lim_{x\to1}\left(\frac{y^2+y}{y-1}\right)$
$\frac{c^6}{121}-d^{12}$
$8+2x+8x+10$
$\frac{dy}{dx}=\frac{1+2y}{1+x}$
$\frac{120}{\left(-8\right)}$
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