$\frac{-6x^2+5x+15}{11x^3-4x+7}$
$\int\left(x^3+x+1\right)^4\left(3x^2+1\right)dx$
$10-\left(-8-\left(15-13\right)\right)$
$y^3=\sqrt{9x^2+4}$
$2xy'\:-3y\:=4x^2$
$25x^2-30x+13=0$
$\left(\frac{6}{5}a-\frac{3}{4}\right)^3$
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