$\lim_{x\to-1}\left(\frac{3x^4+8x^3+4x+9}{x+1}\right)$
$\frac{1}{3}\int\frac{1}{v^{2}-1}dv$
$6x\:9\ge_-\:2x\:5\:$
$\left(6m^4-7\right)^2$
$x^2+\sqrt{3x}+\sqrt{9}$
$\sin\left(a\right)\cos\left(a\right)$
$2-\left(x-2\right)^2$
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