$\int\frac{3x+6}{x^2+18x+81}dx$
$6t-8=2\left(2t+1\right)$
$\left(3x^8+5\right)\left(3x^8+8\right)$
$\left(m^2+11n\right)w\left(3m-11n\right)$
$\frac{a^3b^2\cdot\left(ab^4\right)^{-1}a^{-4}}{ba^{-1}}$
$8x>56+x$
$1265+876$
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