$2sin\left(\frac{\pi\:}{4}x\right)=1$
$\frac{800}{8}$
$-40\left(-4\right)$
$\frac{\left(4x^2-2x\right)}{2x}$
$\int\frac{5}{\left(4+5x\right)^8}dx$
$\frac{dy}{dx}+xy=3x$
$\frac{3}{9}x\frac{18}{3}$
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