$\int x^2\cos\left(\frac{1}{4}x\right)dx$
$x\:dx\:+\:y\:e^{-x}\:dy=o\:\:y\left(o\right)=1$
$\left(5u+3\right)\left(5u-3\right)$
$xy=3cx^3+\frac{3}{x}$
$5\left(m+9\right)+4\left(1+2m\right)$
$-20x-8$
$\left(a^2b^4\right)^2\left(a^{-2}b^3\right)^{-1}a^4$
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