$\int_{-4}^5\left(e^{5x}\right)dx$
$\frac{x^2-3x+2}{x-1}e$
$\frac{d}{dx}6x^9y^5=11x^5$
$3uv^4\cdot u^3v^4$
$0.86=\left(-0.00402\cdot\ln\left(\frac{x}{177.20}\right)^2\right)$
$y^'=e^{-3x}+2x$
$2xy-x^2-9=0$
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