$2^9\cdot2$
$\lim_{x\to\infty}\left(\frac{x\ln\:\left(\frac{x-8}{x}\right)}{4}\right)$
$x^2+6xy+5x^2$
$2a-\frac{6}{a}=a$
$\frac{d^3}{dx^3}\left(x^2lnx\right)$
$\sqrt[4]{405a^5}b^4w^6$
$4+16x^2$
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