$-\:\left(-6+4\right)\:+\:\left(+3-7\right)-\left(+2-10\right)\:$
$1\cdot9a^2$
$\frac{16}{4}$
$x^2-5x=9$
$-5-\left|4-1+3\right|:\left(+2\right)-\left(10-8\right)$
$2b\:-\:3c\:+4b\:-\:6c\:+2c\:-\:2b$
$\frac{1-2\sin^2x}{\cos x+\sin x}+\sin x=\cos x$
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