$1=\left|-1\right|$
$\frac{dy}{dx}+xu=10$
$\frac{2x^3-5x^3-4x+10}{x-1}$
$\lim_{x\to0}\left(\frac{x^2+7x}{cos\left(x\right)-1}\right)$
$2x^2\:-3y-4x+6y$
$x^2+4x+4\le0$
$\frac{dy}{dx}9y=x$
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