$\lim_{x\to\infty}\left(\frac{9x^2+5}{8x^2+3x+1}\right)\frac{1}{x}$
$\frac{x^2+18x+81}{x^3-27}$
$\frac{x+2}{y+1}\frac{dy}{dx}=\frac{x}{y}$
$2x-3\ge x+2$
$y''+y'+y=0$
$\lim_{x\to-\infty}\frac{x^3}{e^{x^2}}$
$-1^3-2^4$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!