$x^2+20xy+100y^2$
$\lim_{x\to0}\left(\frac{5x+tan\left(3x\right)}{5x-tan\left(3x\right)}\right)$
$5z\left(3z-9\right)$
$-r\:+\:8\left(-5r-2\right)$
$16.5m-17.m-16.84=-16.84-m$
$1,91\:+\:-0,772\:$
$2\cdot4+-2$
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