$\left(3m^3-4m^3n\right)^3$
$\frac{dy}{dx}=6tez$
$\lim_{x\to\infty}\frac{8x^3-3x+4}{5-2x^3}$
$4\left(-4\right)\left(-8\right)$
$7-0.3$
$-7p-4z+3p-8+z$
$1-x^5$
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