$\:\frac{1\:+cos\:w}{sen\:w}$
$5^3-6^2-3^3+7^0$
$\left(x-3\right)^2=8\left(y+1\right)$
$12a+4a+a+8a$
$\left(4x^3-x^2-6x-9\right)+\left(12x^3-3x^2+6x\right)$
$\frac{x^3-5x+2}{x^3}$
$\frac{dy}{dx}=4\cdot x-5\cdot y\left(x\right)$
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