$2+\left(-6\right)^{2}$
$\left(-10\right)\:x\:\left(0\right)\:+\:\left(+2\right)$
$8x^2+4x+2$
$3x^2+6x>0$
$x2+14x-33$
$\frac{\left(9x^2-26x-5\right)}{3t^2-5t-2}$
$xdx\:+\left(y-2x\right)dy=0$
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