$\frac{p+5}{p^2+p}=\frac{1}{p^2+p}-\frac{p-6}{p+1}$

$\lim_{x\to-2}\left(2x+3\right)$

$\lim_{x\to\frac{\pi}{2}}\left(\frac{x\left(1-sin\left(x\right)\right)}{\cos\left(x\right)}\right)$

$2\sin\left(-4\:\theta\right)=0$

$s^2+1-5s+2s-1+3s$

$\left(9x+3y\right)^2$

$\frac{1}{16}\int\sqrt{\left(4-x^2\right)}dx$