$\lim_{z\to\infty}\left(\frac{z^2+1}{z-1}\right)$
$\lim_{x\to1}\left(-\frac{4}{x-1}\right)$
$2,5-0,4a-3,6a+4a$
$\frac{1}{2}y^{-2}+\frac{1}{2}^2$
$4^5\cdot2^6$
$\frac{\sqrt{1-x^2}}{1-x^2}$
$5\cdot10^4$
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