$10x^2+20x+10$
$\frac{1}{3}x+14=26$
$x^2+x-10$
$\left(4x+2y+y\right)^2$
$3\left(x+5\right)+6=5+5\left(x+2\right)$
$\left(a^z\right)\left(a^3\right)\left(a^3\right)$
$\frac{3}{x^2}+\frac{3}{x^4}$
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