$9+2.5^2$
$7\cdot\frac{3}{7}$
$\left(2x^5-3x^2\right)^3$
$\lim_{x\to0}\left(\frac{17x}{17x+2}\right)^{9x}$
$\lim_{x\to\infty}\left(\frac{lnx^4}{ln\left(x+1\right)^4}\right)$
$dy\cdot4y^3=\left(3x^2+e^x\right)dx$
$\lim_{x\to-\infty}\:30-5x$
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