$\frac{cot\left(b\right)}{\cos\left(b\right)}+\frac{1}{\sin\left(b\right)}=1$
$-3y^2+2y^3-9y^4$
$599^0$
$9x^2-6x=35$
$\left(-15a^nb^3\right)\cdot\frac{4}{5}ab$
$-16-8-\left(-25\right)-\left(-2\right)$
$\frac{3}{4}\:=\:\frac{1}{4}\:x$
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