$\frac{x^3+4x^2-6x+12}{x-2}$
$-4x^3+x^3+x^3-6y^3+y^3+4y^3-3$
$\frac{d^3}{dx^3}=\frac{3x}{1-x}$
$x^3+3x^2-2$
$\left(7n^2-44n+12\right)$
$-20\:.\:-31$
$2-3x\le6$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!