$16a^2b^4+48ab^2xy^3+36x^2y^6$
$\frac{8x}{x^2+6x-7},\:c=0$
$y^6-81\frac{y^6-81}{y^3-9}$
$5a^3\left(8a+b\right)$
$9a^x+3a^x+8a^x$
$\frac{5x^3+3^2-6x+8}{x^2+8x+6}$
$\left(\sqrt[2]{x}\right)\left(\sqrt[3]{2x^2}\right)$
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