$xy'+y\left(\ln\:\left(\frac{y}{x}\right)-1\right)=0$

$\int_2^{\infty}\left(\frac{1}{\left(\sqrt{1+x^2}\right)}\right)dx$

$\int\left(\frac{1}{\left(1+x^2\right)\tan^{-1}\left(x\right)}\right)dx$

$\frac{1}{2\tan^2\left(x\right)\sqrt{4+2\tan^2\left(x\right)}}$

$\frac{\left(2b\right)\left(2a^{-3}\right)}{2a^{-2}b^2}^4$

$2\cdot x^2\cdot y^5\cdot z^8+4\cdot x^3\cdot y^2\cdot z^5$

$x'=x-x^2t$