$\sin x-0.832=0$
$y'=-y$
$\frac{\left(2x^{-2}y\right)^{-3}}{\left(2xy^{-1}\right)^2}\left(2x^2y^{-7}\right)$
$\left(2m+3n+5\right)^2$
$\left(\frac{1-q^{-1}}{h}\right)^2$
$\lim_{x\to\infty}\left(1+\frac{3}{x}\right)^{9x}$
$x^{2}+3x+8=x+2$
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