$-2^3-2^2$
$\sqrt{x}\sqrt[4]{x}\sqrt[5]{x^3}$
$\lim_{x\to\infty}\left(\frac{x-1}{x+3}\right)^{x+2}$
$\left(4y\right)\left(+7\right)$
$\frac{2x^2+3x+4}{x-1}$
$x^{\left(2\right)}-9x+8<0$
$x\cdot y=8$
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