$\frac{\sin^2x}{\sin2x}$
$\frac{d}{dx}\sqrt{\frac{x}{x+1}^2+9}$
$-5-3-\left(-7+4-3\right)-\left(-8+2-5\right)$
$\lim_{x\to2}\left(\frac{3x^2+2x+1}{x-1}\right)$
$\left(5\right)-\left(2\right)^2+4$
$\left(p\:+\:2b\right)^2$
$\frac{3\left(sinx+cosx\right)^2-3}{sin^2x}=6cotx$
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