$\:\frac{d^2y}{dx^2}=4x+3\:\:$
$\frac{d}{dx}\left(\left(4x-5\right)^4\left(5x^2+4\right)^2\right)$
$-9x^{2}-x^{2}-7x^{2}-6x^{2}+8$
$\left(7+4^3\right)$
$-6c+6c-1$
$\int e^{7x+3}dx$
$a^2b^2-1$
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